For reaction $H I ⇌ 1 / 2 H_{2} + 1 / 2 I_{2}$ value of $K_{c}$ is 1/8 then value of $K_{c}$ for $H_{2} + I_{2} ⇌ 2 H I$ .

\frac{1}{64}

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64

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\frac{1}{8}

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8

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Solution

The correct option is B $64$
$H I ⇌ 1 / 2 H_{2} + 1 / 2 I_{2}$
$K_{C} = {[\frac{1}{1 / 8}]}^{2} = 64$

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If one third of HI decomposed at a particular temperature. What is the value of K_cfor 2HI<======> H₂ + I₂ is

A) 1/16

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