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Relation between Kp and Kc

For reaction ...

Question

For reaction $P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g), K_{c}$ is 30 at 300 K. The value of $K_{p}$ at 300 K is

1.219

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2.43

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3.67

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None of these

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Solution

The correct option is A $1.219$
For a gaseous reaction $2 B \to A$ , the equilibrium constant $K_{p}$ is less than $K_{c}$
$K_{p} = K_{c} (R T)^{Δ n}$
$Δ n = 1 - 2 = - 1$
$K_{p} = K_{c} (R T)^{- 1}$
$K_{P} < K_{c}$
here, $K_{P} = 30 / 300 * 0.083 = 1.2$

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Similar questions

Q. For the reaction

P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g)

the value of

K_{c}

250^{o} C

is 26. The value of

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at this temperature will be :

Q. For the following reaction at

250^{o} C

, the value of

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26

, then the value of

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at the same temperature will be:

P {C l}_{3} (g) + {C l}_{2} (g) ⇌ P {C l}_{5} (g)

For the reaction $P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g)$ at $2500^{\circ} C$ , the value of $K_{C}$ is $26$ , then the value of $K_{P}$ at the same temperature will be

P C l_{5} (g) \to P C l_{3} (g) + C l_{2} (g)

at 298 K,

K_{c} = 1.8 \times 10^{- 7} .

What is

Δ G^{0}

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Q. For the reaction

P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g)

, the value of

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is 26. The value of

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For reaction PCl3(g)+Cl2(g)⇌PCl5(g),Kc is 30 at 300 K. The value of Kp at 300 K is

The correct option is A 1.219For a gaseous reaction 2B→A, the equilibrium constant Kp is less than KcKp=Kc(RT)ΔnΔn=1−2=−1Kp=Kc(RT)−1KP<Kchere, KP=30/300∗0.083=1.2

For reaction $P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g), K_{c}$ is 30 at 300 K. The value of $K_{p}$ at 300 K is

The correct option is A $1.219$
For a gaseous reaction $2 B \to A$ , the equilibrium constant $K_{p}$ is less than $K_{c}$
$K_{p} = K_{c} (R T)^{Δ n}$
$Δ n = 1 - 2 = - 1$
$K_{p} = K_{c} (R T)^{- 1}$
$K_{P} < K_{c}$
here, $K_{P} = 30 / 300 * 0.083 = 1.2$