For real x, let f(x)=x3+5x+1, then
f is one-one and onto R
Given that f(x)=x3+5x+1
∴f′(x)=3x2+5>0,∀x∈R⇒ f(x) is strictly increasing on R⇒ f(x) is one-one
Since f(x) is a polynomial function which is continuous and increasing on R
with limx→−∞f(x)=−∞
and limx→∞f(x)=∞∴ Range of f=(−∞,∞)=R
Hence f is onto also. So, f is one-one and onto R.