The correct option is A 24
L={a2+3korb10+12k}fork≥0
=a2(a3)∗orb10(b12)∗
={a2,a5,a8,...,b10,b22,b34....}
The pumping length is p, than for any string w ϵ L with ∣w∣≥p must have a repetition i.e. such a string must be breakable into w = xyz such that ∣y∣≥0 and y can be pumped indefinitely, which is same as saying xyz ϵ L
⇒xy∗z ϵ L.
The minimum pumping length in this language is clearly 11, since b10 is a string which has no repetition number, so upto 10 no number can serve as a pumping length. Minimum pumping length is 11. Any number at or above minimum pumping length can serve as a pumping length. The only number at or above 11, in the choice given is 24.
So correct answer is option (b).