CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For Σ={ a, b} let us consider the regular language
L = {xx=a2+3korx=b10+12k,k0} Which one of the following can be a pumping length (the constant guaranteed by the pumping lemma ) for L?

A
24
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 24
L={a2+3korb10+12k}fork0

=a2(a3)orb10(b12)

={a2,a5,a8,...,b10,b22,b34....}


The pumping length is p, than for any string w ϵ L with wp must have a repetition i.e. such a string must be breakable into w = xyz such that y0 and y can be pumped indefinitely, which is same as saying xyz ϵ L

xyz ϵ L.

The minimum pumping length in this language is clearly 11, since b10 is a string which has no repetition number, so upto 10 no number can serve as a pumping length. Minimum pumping length is 11. Any number at or above minimum pumping length can serve as a pumping length. The only number at or above 11, in the choice given is 24.

So correct answer is option (b).

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Simple and Compound Interest
Watch in App
Join BYJU'S Learning Program
CrossIcon