Question

For slaking of $15\text{kg}$ of CaO, the theoretical amount of water required is

• A. $1.6\text{kg}$
• B. $2.4\text{kg}$
• C. $4.82\text{kg}$
• D. $4.0\text{kg}$

Answer 1

The correct option is C $4.82\text{kg}$

$CaO+H_{2}O\to Ca(OH{)}_2$
$\because 56g$ of CaO requires 18 g of water
$\therefore 15\text{kg}$ of CaO required $\frac{18}{56}\times 15\text{kg}=4.82\text{kg}$ of water