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Question

For solving dydx=4x+y+1=v, the suitable substitution is

A
y=vx
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B
y=4x+v
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C
y=4x
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D
y=4x+1=v
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Solution

The correct option is D y=4x+1=v
dydx=4x+y+1
Substitute 4x+y+1=v. Differentiating w.r.t x, we get
4+dydx=dvdxdydx=dvdx4
dvdx4=vdvdx=4+v
dv4+v=dxdv4+v=dx
log(4+v)=x+c

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