For solving each pair of equations, use the method of eliminations by equating coefficients:

$\frac{x - y}{6} = 2 (4 - x)$

$2 x + y = 3 (x - 4)$

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Solution

$\frac{x - y}{6} = 2 (4 - x) x - y = 12 (4 - x) x - y = 48 - 12 x 12 x + x - y = 48 13 x - y = 48 - - - - (1) 2 x + y = 3 (x - 4) 2 x + y = 3 x - 12 2 x - 3 x + y = - 12 - x + y = - 12 x - y = 12 - - - - (2) m u l t i p l y (2) b y 13 13 x - 13 y = 156 - - - - (3) 13 x - y = 48 - - - - (1) (3) - (1) - 12 y = 108 y = - 9 P u t v a l u e o f y i n (2) x - y = 12 x + 9 = 12 x = 3$

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