For solving each pair of equations, use the method of eliminations by equating coefficients:
15(x−2)=14(1−y)
26x+3y+4=0
Multiplying equation no. (1) by 3 and(2) by 5.
From (1)
3−(x−5)=y+2
2(x+y)=4−3y
y=2x−6
y=0
41x+53y=135
53x+41y=147
Solve the pair of linear equations using cross-multiplication method.
5(x−2)=4(1−y)