Question

For $\sqrt{2}{x}^2-5x+\sqrt{2}=0$ then value of discriminant is ______

• A. $-5$
• B. $17$
• C. $\sqrt{2}$
• D. $2\sqrt{2}-5$

Answer 1

Answer: (B)

$17$

$\sqrt{2}{x}^2-5x+\sqrt{2}=0$

$D=b^2-4ac$

$D=(-5)(-5)-4\left(\sqrt{2}\right)\left(\sqrt{2}\right)$

$D=25-8=17$