For testing halogens in an organic compound with $A g N O_{3}$ solution, sodium extract (Lassaigne's test) is acidified with dilute $H N O_{3}$ . What will happen if a student acidifies the extract with dilute $H_{2} S O_{4}$ in place of dilute $H N O_{3}$ ?

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Solution

On adding dilute $H_{2} S O_{4}$ for testing halogens in an organic compound with $A g N O_{3}$ , white precipitate of $A g_{2} S O_{4}$ is formed. This will interfere with the test of chlorine and this $A g_{2} S O_{4}$ may be mistaken for white precipitate of chlorine as $A g C l$ . Hence, dilute $H N O_{3}$ is used instead of dilute $H_{2} S O_{4} .$

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