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Question

For the 1s orbital of the Hydrogen atom, the radial wave function is given as: R(r)=1π(1a0)32era0 (Where a0=0.529 A)
The ratio of radial probability density of finding an electron at r=a0 to the radial probability density of finding an electron at the nucleus is given as (x.ey).
Calculate the value of (x+y).

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Solution

Radial probability density =[R(r)]2
So [R(ao)]2[R(0)]2=e2ao/aoe0=e2
Here, x=1, y=2

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