For the 4 bit DAC shown below, the Analog output voltage is (Assume ideal Op-amp).

- 1.11 V

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- 2.4 V

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- 3.25 V

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- 3.75 V

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Solution

The correct option is D
$- 3.75 V$

$I = \frac{10 - 0}{10 K} = 1 m A I_{1} = \frac{I}{8} + \frac{I}{16} = \frac{1}{8} + \frac{1}{16} = \frac{3}{16} m A V_{0} = - I_{1} \times 20 K = \frac{- 3}{16} \times 20 = \frac{- 15}{4} = - 3.75 V o l t s$

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