Question

For the 4 bit DAC shown in the figure, the output voltage $V_0$ is

• A. 10 V
• B. 5 V
• C. 4 V
• D. 8 V

Answer 1

The correct option is B 5 V

$V_{in}$ at non-inverting terminal $=\frac{1}{8}+\frac{1}{2}=\frac{5}{8}V$
$\therefore V_0=(1+\frac{R_f}{R})V_{in}$
$V_0=8\times \frac{5}{8}=5V$