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R-2R Ladder DAC

For the 4 bit...

Question

For the 4 bit DAC shown in the figure, the output voltage $V_{0}$ is

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Solution

$V_{i n}$ at non-inverting terminal $= \frac{1}{8} + \frac{1}{2} = \frac{5}{8} V$
$∴ V_{0} = (1 + \frac{R_{f}}{R}) V_{i n}$
$V_{0} = 8 \times \frac{5}{8} = 5 V$

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