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Question

For the A.P.: -3,-7,-11,..., can we find a30a20 without actually finding a30 and a20? Give reasons for your answer. 


Solution


anak=a+(n1)d[a+(k1)d]anak=(n1)d(k1)danak=d[nk]So,a30a20=4(3020)=4×10=40

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