For the above reaction, addition of $L i A l H_{4}$ in dry ether takes place at low temperature $(- 10^{o} C)$ . What would be the product (B)?

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Solution

The correct option is C

Low temperature favours the reduction of carbonyl group only into alcohol by $L i A l H_{4} / dry ether$ . The alkene will remain unaffected.

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For the above reaction, addition of LiAlH4 in dry ether takes place at low temperature (−10 oC). What would be the product (B)?

The correct option is C Low temperature favours the reduction of carbonyl group only into alcohol by LiAlH4/dry ether. The alkene will remain unaffected.

For the above reaction, addition of $L i A l H_{4}$ in dry ether takes place at low temperature $(- 10^{o} C)$ . What would be the product (B)?

The correct option is C

Low temperature favours the reduction of carbonyl group only into alcohol by $L i A l H_{4} / dry ether$ . The alkene will remain unaffected.