Question

For the AP $\frac{3}{2}$, $\frac{1}{2}$, $-\frac{1}{2}$, $-\frac{3}{2}$,.. write the next two terms after the given last term $-\frac{3}{2}$.

• A. Here, the next two terms after the given term $-\frac{3}{2}$ are $-\frac{5}{2}$, $-\frac{7}{2}$
• B. Here, the next two terms after the given term $-\frac{3}{2}$ are $-\frac{5}{2}$, $-\frac{9}{2}$
• C. Here, the next two terms after the given term $-\frac{3}{2}$ are $-\frac{4}{2}$, $-\frac{7}{2}$
• D. None of these
  

Answer 1

The correct option is A Here, the next two terms after the given term $-\frac{3}{2}$ are $-\frac{5}{2}$, $-\frac{7}{2}$

First term $a=\frac{3}{2}$, common difference $d=\frac{1}{2}-\frac{3}{2}=-1$.
$nth$ term=$a_n=a+(n-1)d$

$\therefore a_5=a+4d=\frac{3}{2}+4\times -1=\frac{-5}{2}$

$a_6=a+5d=\frac{3}{2}+5\times -1=\frac{-7}{2}$