wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For the AP: x7,x2,x+3,.... the 15th term is ____.


A

x+53

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

x53

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

x63

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

x+63

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

x+63


Given AP is: x7,x2,x+3,....
First term (a)=x7

Common difference: (d)=(x2)(x7)=5

The nth term of an AP is given by, an=a+(n1)d

Then, the 15th term of the above series is given by,

a15=(x7)+(151)5

a15=x7+70 =x+63


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon