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Question

For the arrangement shown in figure, the tension in the string to prevent it from sliding down is

A
6 N
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B
64 N
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C
0.4 N
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D
None of these
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Solution

The correct option is D None of these
Since μ=0.8=45
Angle of repose α=39
Since angle which incline makes with the horizontal is 37(<39), so the block will not slide down the incline and friction between the block and the incline will be static in nature. So,
fs=Fapplied=mg sin(37)

Now, if T be the tension in the string, then
T+fs=mg sin(37)
T=0 {fs=mg sin(37)}
Hence, the correct answer is (d).

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