Question

# For the arrangement shown in figure, the tension in the string to prevent it from sliding down is

A
6 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
64 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.4 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D None of theseSince μ=0.8=45 ⇒ Angle of repose α=39∘ Since angle which incline makes with the horizontal is 37∘(<39∘), so the block will not slide down the incline and friction between the block and the incline will be static in nature. So, fs=Fapplied=mg sin(37∘) Now, if T be the tension in the string, then T+fs=mg sin(37∘) ⇒T=0 {∵fs=mg sin(37∘)} Hence, the correct answer is (d).

Suggest Corrections
8
Join BYJU'S Learning Program
Related Videos
Warming Up: Playing with Friction
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program