Question

For the arrangement shown in the figure, the force at the bottom of the vessel is [Take $g=10{\text{m/s}}^2$]

• A. $200\text{N}$
• B. $100\text{N}$
• C. $20\text{N}$
• D. $2\text{N}$

Answer 1

The correct option is B $100\text{N}$

Asnwe know,
$F=P\times A$
where, $P=$ Pressure at the bottom of the vessel
$A=$ Area of the base of the vessel =$100{\text{cm}}^2$
i.e $F=\left(\rho g{h}_{\text{total}}\right)\times A$
Here, $h_{\text{total}}=(99+1)\text{cm}=1\text{m}$
$\Rightarrow F=({10}^3\times 10\times 1)\times (100\times {10}^{-4})$
$\Rightarrow F=100\text{N}$