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Question

For the arrangement shown in the figure, the reading of spring balance is:

236234_456ba54e2f06413db35b8c089b968d09.png

A
50N
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B
100N
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C
150N
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D
None of the above
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Solution

The correct option is D None of the above
Step 1: Acceleration of system [Refer Fig.]
String and spring are massless
Apply Newton's second law on 5 kg
ΣF=ma
T5g=5a ....(1)

Apply Newton's second law on 10 kg
ΣF=ma
10gT=10a ....(2)

Adding equation (1) and (2)
a=5g15=5×1015=103 m/s2

Step 2: Reading of spring balance
Reading of spring balance will be force responsible for its elongation.
Tension is responsible for the elongation of spring.
From equation (2)
10gT=10a

10×10T=10×103 T=2003N
Reading of spring balance =2003 N

Hence, Option D is correct

2108951_236234_ans_0d058b1436414f71a8c85f0d6da76411.png

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