You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Inductors in Circuits

For the arran...

Question

For the arrangement shown in the figure, the switch is closed at $t = 0. C_{2}$ is initially uncharged while $C_{1}$ has a charge of $2 μ C$ . Find the charge on the capacitors in the steady state condition.

Open in App

Solution

In the steady state, the capacitors are fully charged so no current will flow through the circuit. Thus, the capacitor $C_{2}$ will be short-circuit. So potential across $C_{2}$ is zero and potential across $C_{1}$ will be $9 V$

Using $Q = C V$ ,
the charge on $C_{1}$ is $Q_{1} = 1 \times 9 = 9 μ C$ and the charge on $C_{2}$ is $Q_{2} = 2 \times 0 = 0 μ C$

Suggest Corrections

Similar questions

Q. For the arrangement shown in the figure, the key is closed at

t = 0

C_{2}

is initially uncharged while

C_{1}

has a charge of

2 μ C

.
(a) Find the current coming out of the battery just after switch is closed.
(b) Find the charge on the capacitors in the steady state condition.

Q. For the arrangement shown in the figure, the switch is closed at

t = 0. C_{2}

is initially uncharged while

C_{1}

has a charge of

2 μ C

. Find the current coming out of the battery just after the switch is closed.

Q. Two capacitors

C_{1}

and

C_{2} = 2 C_{1}

are connected in a circuit with a switch between them as shown in the figure. Initially the switch is open and

C_{1}

holds charge Q. The switch is closed. At steady state, the charge on each capacitor will be :

In the circuit shown below, initially the switch $S_{1}$ is open, the capacitor C1 has a charge of 6 coulomb, and the capacitor C2 has 0 coulomb. After $S_{1}$ is closed, the charge on C2 in steady state is Coulomb.

Q. In the circuit shown in figure

C_{1} = C_{2} = C

and capacitor

C_{1}

having initial charge

Q

, the switch is closed at

t = 0

. Then _______

Join BYJU'S Learning Program

For the arrangement shown in the figure, the switch is closed at t=0.C2 is initially uncharged while C1 has a charge of 2μC. Find the charge on the capacitors in the steady state condition.

In the steady state, the capacitors are fully charged so no current will flow through the circuit. Thus, the capacitor C2 will be short-circuit. So potential across C2 is zero and potential across C1 will be 9VUsing Q=CV, the charge on C1 is Q1=1×9=9μC and the charge on C2 is Q2=2×0=0μC

For the arrangement shown in the figure, the switch is closed at $t = 0. C_{2}$ is initially uncharged while $C_{1}$ has a charge of $2 μ C$ . Find the charge on the capacitors in the steady state condition.