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Question

For the arrangement shown in the figure. The velocity of image with respect to ground will be:
[All the velocities are given with respect to ground]



A
2 cm/s in +y direction
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B
2 cm/s in y direction
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C
4 cm/s in +y direction
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D
4 cm/s in y direction
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Solution

The correct option is A 2 cm/s in +y direction
For the given concave mirror,
u=30 cm, f=20 cm
Relative velocity of object with respect to mirror in perpendicular to the principal axis,
vom=vogvmg=22=0
Also, velocity of the image when the object is moving perpendicular to the principal axis,
vim=mvom
vim=0
Now, the velocity of the image with respect to ground,
vig=vim+vmg
vig=0+2=2 cm/s
Hence, the velocity of the image with respect to ground will be 2 cm/s in +y direction.
Why this question?

Caution: In excitement you may mark 'zero' as image velocity. Always remember about which respect the image velocity has been asked.

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