Question

For the beam having a uniformly distributed load of w per unit length as shown in the given figure, the maximum positive bending moment is equal to maximum negative bending moment. The value of $L_1$ and L for this condition is :

• A. $\frac{1}{\sqrt{2}}$
• B. $\sqrt{2}$
• C. $\frac{1}{2}$
• D. $\frac{1}{2\sqrt{2}}$

Answer 1

The correct option is D

$\frac{1}{2\sqrt{2}}$

(d)


To ensure the hogging bending moment at two points of suspension is equal to sagging bending moment.

So, $L_1=\frac{(L+2L_1)-2L_1}{2\sqrt{2}}$

$=\frac{L}{2\sqrt{2}}$

$\therefore \frac{L_1}{L}=\frac{1}{2\sqrt{2}}$