You visited us 1 times! Enjoying our articles? Unlock Full Access!

Nernst Equation

For the cell,...

Question

For the cell, $P t, H_{2} (g) | 2 M C H_{3} C O O N H_{4} | | 2 M N a C l | H_{2} (g), P t$
20 atm 0.2 atm
Given : $p K_{a} (C H_{3} C O O H) = 4.74$ and $p K_{b} (N H_{4} O H) = 4.74$
EMF of the cell in millivolt is: (Given $\frac{2.303 R T}{F} = 0.059)$

Open in App

Solution

pH of $2 M C H_{3} C O O N H_{4}$ solution is 7 since $p K_{a} = p K_{b}$

the pH of $2 M N a C l$ solution is 7 since it is salt of strong acid and strong base.

Now,

$E = E_{c e l l}^{\circ} - \frac{0.059}{2} . log Q$
$Q = \frac{(10^{- 7})^{2}}{20} \times \frac{0.2}{(10^{- 7})^{2}} = \frac{1}{100}$
$E = 0 - \frac{0.059}{2} . log \frac{1}{100} = \frac{0.059}{2} \times 2 = 0.059$
$1000 E = 1000 \times 0.059 = 59$

Hence, the answer is $59$

Suggest Corrections

Similar questions

P t, H_{2} (g) | 2 M C H_{3} C O O N H_{4} (a q) | | 2 M N a C l (a q) | H_{2} (g), P t

p K_{a} o f C H_{3} C O O H = 4.74 a n d p K_{b} o f N H_{4} O H i s 4.74

E

\frac{2.303 R T}{F} = 0.059

H g O (s) + H_{2} (g) \to H g (ℓ) + H_{2} O (ℓ)

H g O (s) + H_{2} (g) \to H g (l) + H_{2} O (l)

P t,

H_{2}

1

H O C N

(10^{- 3} M) | | A g^{+} (0.8 M) | A g (s)

0.98

K_{a}

H O C N

[H^{+}]

H_{2} (g)

\frac{2.303 R T}{F} = 0.06

P t (s), H_{2} (g) | 1 b a r H C l (a q) | A g (s) | P t (s)

0.92

10^{- 6}

H C l

(A g C l / A g, C l^{-})

\frac{2.303 R T}{F} = 0.06 V

298 K

Join BYJU'S Learning Program