For the cell reaction- Mgs - 2Ag-aq- - Mg2-aq- - 2Ags E-cell is -3-17 V at 298 K- The value of Ecell- G- and Q at Ag- and Mg2- concentrations of 0-001 M and 0-02 M respectively are-

The correct option is D 3.04 V, 611.8 kJ, 20000 E^∘ = + 3.17 V, n = 2 Q = [Mg^2+][Ag^+]^2 = 0.02[0.001]^2 = 20000 G^∘ = nFE^∘ = 2× 9 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

EMF

For the cell ...

Question

For the cell reaction,
$M g (s) + 2 A g^{+} (a q .) ⇌ M g^{2 +} (a q .) + 2 A g (s)$
$E_{c e l l}^{\circ}$ is $+ 3.17 V$ at $298 K$ . The value of $E_{c e l l}, △ G^{\circ}$ and $Q$ at $A g^{+}$ and $M g^{2 +}$ concentrations of $0.001 M$ and $0.02 M$ respectively are:

3.04 V, - 605.8 k J m o l^{- 1}, 20000

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3.04 V, 611.8 k J m o l^{- 1}, 20000

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3.13 V, - 604 k J m o l^{- 1}, 20

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3.04 V, - 611.8 k J, 20000

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

25^{\circ} C

M g (s) + 2 A g^{+} (a q) ⇌ M g^{2 +} (a q) + 2 A g (s)

E_{c e l l}^{0} = + 3.17 V

E_{c e l l}, Δ G^{0} and Q

[A g^{+}] = 10^{- 3} M

[M g^{2 +}] = 0.02 M

Q is reaction quotient

l o g 2 = 0.301

M g_{(s)} + 2 A g_{(a q)}^{+} \to M g_{(a q)}^{2 +} + 2 A g_{(s)}

E_{M g^{2 +} / M g}^{0} = - 2.37 V

E_{A g^{+} / A g}^{0} = 0.80 V

[M g^{2 +}] = 0.001 M; [A g^{+}] = 0.0001 M

M g + 2 {A g}^{+} (0.0001 M) \to {M g}^{2 +} (0.01 M) + 2 A g

E_{c e l l}^{o} = 3.177 V

E_{c e l l}

M g (s) + 2 A g^{+} (0.0001 M) \to M g^{2 +} (0.130 M) + 2 A g (s)

E_{(c e l l)} if E_{(c e l l)}^{o} = 3.17 V

C u (s) + 2 A g^{+} (a q .) \to C u^{2 +} (a q .) + 2 A g (s)

E_{c e l l}^{\circ} = 0.46 V

C u^{2 +}, E_{c e l l}^{\circ}

Join BYJU'S Learning Program