For the cell reaction- C1Cu2-aq- - Zns -C2Zn2-aq- - Custhe change in free energy G at a given temperature is a function of-

The correct option is B RT ln (C_2C_1 ) Gibbs free energy G^∘= RT ln K ———–1For reaction: Cu_(aq)^2++Zn_(s)→ Zn_(aq)^2++Cu_(s) K=ProductRea ...

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Byju's Answer

Standard XII

Chemistry

Nernst Equation

For the cell ...

Question

For the cell reaction,
$C u^{2 +} (C_{1}) (a q .) + Z n (s) \to Z n^{2 +} (C_{2}) (a q .) + C u (s)$
the change in free energy $(△ G)$ at a given temperature is a function of____________.

l n C_{1}

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- R T l n (\frac{C_{2}}{C_{1}})

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l n (C_{1} + C_{2})

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l n C_{2}

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Solution

The correct option is B $- R T l n (\frac{C_{2}}{C_{1}})$
Gibbs free energy $△ G^{\circ} = - R T l n K$ -----------1
For reaction:-
$C u_{(a q)}^{2 +} + Z n_{(s)} \to Z n_{(a q)}^{2 +} + C u_{(s)}$
$K = \frac{P r o d u c t}{R e a c t a n t} = \frac{[Z n_{(a q)}^{2 +}] [C u_{(s)}]}{C u_{(a q)}^{2 +}] [Z n_{(s)}]} = \frac{C_{2}}{C_{1}}$ ---------------2
[In pure form, $C u_{s}$ & $Z n_{(s)} = 1$ ]
$∴ △ G^{\circ} = - R T l n (\frac{C_{2}}{C_{1}})$ ------------From Equation 1 & 2.

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Similar questions

Q. Calculate the equilibrium constant and free energy change of given following reaction for Daniell cell at 298 K temperature.

Z n_{(s)} + C u_{(a q)}^{2 +} ⇌ Z n_{(a q)}^{2 +} + C u_{(s)}

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For the cell reaction : $C u^{2 +} (a q) (C_{1}) + Z n (s) \to Z n^{2 +} (a q) (C_{2}) + C u (s)$ the change in free energy $Δ G$ at a given temperature is a function of

Q. For the cell reaction,

C u_{(a q)}^{2 +} (c_{2}) + Z n_{(s)} \to Z n_{(a q)}^{2 +} (c_{1}) + C u_{(s)}

the change in free energy

(Δ G)

at a given temperature is a function of:

Q. In the galvanic cell :

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E_{c e l l} - E_{c e l l}^{o} = + 0.0591 V

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For the cell reaction,Cu2+(C1)(aq.)+Zn(s)→Zn2+(C2)(aq.)+Cu(s)the change in free energy (△G) at a given temperature is a function of____________.

The correct option is B −RTln(C2C1)Gibbs free energy△G∘=−RTlnK-----------1For reaction:-Cu2+(aq)+Zn(s)→Zn2+(aq)+Cu(s)K=ProductReactant=[Zn2+(aq)][Cu(s)]Cu2+(aq)][Zn(s)]=C2C1---------------2[In pure form, Cus & Zn(s)=1]∴△G∘=−RTln(C2C1)------------From Equation 1 & 2.

For the cell reaction,
$C u^{2 +} (C_{1}) (a q .) + Z n (s) \to Z n^{2 +} (C_{2}) (a q .) + C u (s)$
the change in free energy $(△ G)$ at a given temperature is a function of____________.