For the cell reaction-Zn s - Cu 2-0-1 M - Zn 2-0-01 M - Cu s If E0 is the standard emf of the cell at 298 K- then-A- E-E0B- E-E0C- E - E 0D- E -0

The correct option is B E gt;E^0E = E^0 0.0592 log[Zn^2+][Cu^2+] = E^0 0.0592 log0.010.1 = E^0 0.0592 log110, E = E^0 + 0.0295 ∴ E gt; E^0 ...

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Question

For the cell reaction:
$Z n (s) + C u^{2 +} (0.1 M) \to Z n^{2 +} (0.01 M) + C u (s)$
If $E^{0}$ is the standard emf of the cell at 298 K, then:

E = E^{0}

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E > E^{0}

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E < E^{0}

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E = 0

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Solution

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Similar questions

C u^{2 +}

\to Z n^{2 +}

E^{0}

Z n (s) + C u^{2 +} (0.1 M) \to Z n^{2 +} (0.01 M) + C u (s)

E^{0}

E M F

Z n | Z n^{2 +} (0.01 M) | | C u^{2 +}] (0.1 M) | C u

298 K

E^{\circ}

Z n \to Z n^{2 +} + 2 e^{-}; E^{\circ} = 0.76 V

C u \to C u^{2 +} + 2 e^{-}; E^{\circ} = 0.34 V

Z n (s) + C u^{2 +} \to Z n^{2 +} + C u (s)

E

E_{0}

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