For the cell reaction-Zns - Cu2- aq - Cus - Zn2-aqEcell- - 1-10 V- G- is-

We know, G^∘ = nFE_cell^∘ Here, E_cell^∘=1.10 V ∴ G^∘= 2 × 96500 × 1.10 = 212300 J = 212.3 kJ ...

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Arrhenius Equation

For the cell ...

Question

For the cell reaction:
$Z n (s) + C u^{2 +} (a q) \to C u (s) + Z n^{2 +} (a q)$
$E_{c e l l}^{\circ} = 1.10 V, △ G^{\circ}$ is:

212.3 kJ

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106.05 kJ

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- 212.3 kJ

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- 424.6 kJ

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Solution

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Z n (s) + C u^{2 +} (a q) \to C u (s) + Z n^{2 +} (a q)

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