For the cell:-
$T l (s) | T l^{+} (0.001 M) | | C u^{2 +} (0.1 M) | C u (s); E_{c e l l} = 0.83 V$ at $298 K$ . The cell potential can be increased by :

Increasing

[C u^{2 +}]

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Increasing

[T l^{+}]

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Decreasing

[C u^{2 +}]

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Decreasing

[T l^{+}]

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Solution

The correct options are
A Increasing $[C u^{2 +}]$
D Decreasing $[T l^{+}]$
Cell reaction is $T l_{(s)} + C u_{(a q)}^{2 +} ⇌ T l_{(a q)}^{+} + C u_{(s)}$

Reaction quotient $Q = \frac{[T l^{+}]}{[C u^{2 +}]}$ and

Nernst equation is $E_{c e l l} = E_{c e l l}^{0} - \frac{0.0591}{n} l o g Q$ ; at $298 K$

To increase $E_{c e l l}, Q$ should be decreased. Which is decreased by decreasing $[T l^{+}]$ and increasing $[C u^{2 +}]$ .

Suggest Corrections

Similar questions

T l | T l^{+} (0.001 M) | | C u^{2 +} (0.1 M) | C u

E_{c e l l}

25^{o}

T l_{(s)} | T l^{+} (0.001 M) | | C u^{2 +} (0.1 M) | C u_{(s)} :

E_{c e l l}

For the cell:

${T l}_{(s)}$ / ${T l}^{+}$ (0.001M)// ${C u}^{+ 2}$ (0.1M)/ ${C u}_{(s)}$ :

$E_{c e l l}$ = 0.83V at 298K, The cell potential can be increased by

T l_{(s)} | T l^{+} (0.001 M) | | C u^{+ 2} (0.1 M) | C u_{(s)}

E_{c e l l} = 0.83 V

Z n (s) | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u (s)

E_{c e l l}

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