For the cell:
$T l_{(s)} | T l^{+} (0.001 M) | | C u^{2 +} (0.1 M) | C u_{(s)} :$
$E_{c e l l}$ = 0.83 V at 298 K, The cell potential can be increased by

i n c r e a s i n g [C u^{2 +}]

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i n c r e a s i n g [T l^{+}]

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d e c r e a s i n g [C u^{2 +}]

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d e c r e a s i n g [T l^{+}]

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Solution

The correct options are
A $i n c r e a s i n g [C u^{2 +}]$
D $d e c r e a s i n g [T l^{+}]$
The cell reaction is:
$T l_{(s)} + C u_{a q}^{2 +} ⇌ T l_{a q}^{+} + C u_{(s)}$
$Q_{c} = \frac{T l^{+}}{C u^{2 +}}$
$E = E^{0} - \frac{0.0591}{n} l o g Q_{c} a t 298 k$
$E = E^{0} - \frac{0.059}{n} l o g (\frac{[T l^{+}]}{[C u^{2 +}]})$

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Similar questions

T l (s) | T l^{+} (0.001 M) | | C u^{2 +} (0.1 M) | C u (s); E_{c e l l} = 0.83 V

298 K

T l | T l^{+} (0.001 M) | | C u^{2 +} (0.1 M) | C u

E_{c e l l}

25^{o}

For the cell:

${T l}_{(s)}$ / ${T l}^{+}$ (0.001M)// ${C u}^{+ 2}$ (0.1M)/ ${C u}_{(s)}$ :

$E_{c e l l}$ = 0.83V at 298K, The cell potential can be increased by

T l_{(s)} | T l^{+} (0.001 M) | | C u^{+ 2} (0.1 M) | C u_{(s)}

E_{c e l l} = 0.83 V

Z n (s) | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u (s)

E_{c e l l}

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