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Question

For the cell:
Tl(s)|Tl+(0.001M)||Cu2+(0.1M)|Cu(s):
Ecell = 0.83 V at 298 K, The cell potential can be increased by

A
increasing [Cu2+]
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B
increasing [Tl+]
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C
decreasing [Cu2+]
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D
decreasing [Tl+]
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Solution

The correct option is D decreasing [Tl+]
The cell reaction is:
Tl(s)+Cu2+aqTl+aq+Cu(s)
Qc=Tl+Cu2+
E=E00.0591nlog Qc at 298 k
E=E00.059nlog ([Tl+][Cu2+])

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