For the cell, $T l | T l^{+} (0.001 M) | | C u^{2 +} (0.1 M) | C u$ , the $E_{c e l l}$ at $25^{o}$ C is 0.83V which can be increased by:

increasing

[C u^{2 +}]

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increasing

[T i^{+}]

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decreasing

[C u^{2 +}]

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decreasing

[T l^{+}]

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Solution

The correct options are
A decreasing $[T l^{+}]$
B increasing $[C u^{2 +}]$
The expression for the cell potential is $E_{c e l l} = E_{c e l l}^{0} - \frac{0.0592}{n} l o g \frac{[T l^{+}]}{[C u^{2 +}]}$
Thus, when $[C u^{2 +}]$ is increased or $[T l^{+}]$ is decreased, the value of the term $\frac{0.0592}{n} l o g \frac{[T l^{+}]}{[C u^{2 +}]}$ decreases.
Hence, the value of the cell potential increases.

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Similar questions

T l (s) | T l^{+} (0.001 M) | | C u^{2 +} (0.1 M) | C u (s); E_{c e l l} = 0.83 V

298 K

T l_{(s)} | T l^{+} (0.001 M) | | C u^{2 +} (0.1 M) | C u_{(s)} :

E_{c e l l}

For the cell:

${T l}_{(s)}$ / ${T l}^{+}$ (0.001M)// ${C u}^{+ 2}$ (0.1M)/ ${C u}_{(s)}$ :

$E_{c e l l}$ = 0.83V at 298K, The cell potential can be increased by

T l_{(s)} | T l^{+} (0.001 M) | | C u^{+ 2} (0.1 M) | C u_{(s)}

E_{c e l l} = 0.83 V

E

C u | {C u}^{2 +} (0.001 M) | | {C u}^{2 +} (0.1 m) | C u

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