Question

For the change $H_{2}O\left(s\right),$ (273 K, 2 atm) $\to H_{2}O\left(l\right),$ (273K, 2 atm), choose the correct option.

• A. $\Delta G=0$
• B. $\Delta G<0$
• C. $\Delta G>0$
• D. None

Answer 1

The correct option is B $\Delta G<0$

$H_{2}O\left(s\right)\to H_{2}O\left(l\right),$
At P $=$ 1 atm, $\Delta G=0,$ there is equilibrium at 273 K.
Hence, as P $\uparrow ,$ more $H_{2}O\left(l\right)$ is formed.