For the chemical equilibrium, $C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g), △ H^{o},$ can be determined from which one of the following plots

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Solution

The correct option is A
For the reaction,
$C a C O_{3 (g)} ⇌ C a O_{i} + C O_{2 (g)}$

$K_{p} = P_{C O_{2}} a n d K_{C} = [C O_{2}]$
([ $C a C O_{3}]$ = 1 and [CaO] = 1 for solids]
According to Arrhenius equation we have
$K = A e^{△ H^{o}, / R T}$
Taking logarithm, we have
log $K_{p} = l o g A - \frac{△ H^{o},}{R T (2.303)}$

This is an equation of straight line. When log $K_{p}$ is plotted against 1/T. We get a straight line.

The intercept fo this line = log A, slope = $- △ H^{o}, / 2.303 R$
Knowing the value of slope from the plot and universal gas constant R, $△ H_{r}^{o}$ can be calculated.

Equation of straight line : Y = mx + C. Here, log $K_{p} = - \frac{△ H_{r}^{o}}{2.303 R} (\frac{1}{T}) + l o g A$

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