Question

For the chemical reaction $l^{\ominus }+OC{l}^{\ominus }\to C{l}^{\ominus }+O{I}^{\ominus }$

$Rate=\frac{k\left[OC{l}^{\ominus }\right]\left[l^{\ominus }\right]}{[OH{]}^{\ominus }}$ The order and molecularity of the reaction is:

• A. $1,2$
• B. $2,1$
• C. $2,2$
• D. $3,2$

Answer 1

The correct option is A $1,2$

$l^{\ominus }+OC{l}^{\ominus }\to C{l}^{\ominus }+O{I}^{\ominus }$

1 1

$Rate=\frac{k\left[OC{l}^{\ominus }\right]\left[l^{\ominus }\right]}{[OH{]}^{\ominus }}$

So order is = $1+1-1=1$

and molecularity of the reaction $=1+1=2$