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Byju's Answer

Standard X

Physics

Resistance

For the circu...

Question

For the circuit show in the diagram find the value of Va - Vb after long time closing the switch S1

4 V

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8 V

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V 48

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V 24

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Solution

The correct option is A 4 V
$\begin{matrix} R_{e q} = \frac{3 \times 6}{9} = 2 Ω i = 12 A i_{1} = \frac{12}{9} \times 6 = 8 A i_{2} = 4 A \Rightarrow V_{a} + 3 i_{2} - i_{1} = V_{b} \Rightarrow V_{a} + 12 - 8 = V_{b} \Rightarrow | V_{a} - V_{b} | = 4 V \end{matrix}$
$∴$ Option $A$ is correct .

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For the circuit show in the diagram find the value of Va - Vb after long time closing the switch S1

The correct option is A 4 VReq=3×69=2Ωi=12Ai1=129×6=8Ai2=4A⇒Va+3i2−i1=Vb⇒Va+12−8=Vb⇒|Va−Vb|=4V∴ Option A is correct .

The correct option is A 4 V
$\begin{matrix} R_{e q} = \frac{3 \times 6}{9} = 2 Ω i = 12 A i_{1} = \frac{12}{9} \times 6 = 8 A i_{2} = 4 A \Rightarrow V_{a} + 3 i_{2} - i_{1} = V_{b} \Rightarrow V_{a} + 12 - 8 = V_{b} \Rightarrow | V_{a} - V_{b} | = 4 V \end{matrix}$
$∴$ Option $A$ is correct .