Question

For the circuit shown below, the magnitude of ratio, $\left|\frac{V_0}{V_S}\right|$ will be

• A. $\frac{1}{CR}$
• B. $\frac{1}{\omega CR}$
• C. $\omega$CR
• D. RC

Answer 1

The correct option is C $\omega$CR

We know, $\frac{Cd{V}_s}{dt}=-\frac{V_0}{R}$

$V_0=-RC\frac{d{V}_s}{dt}$

In frequency domain,

$\frac{V_0}{V_S}=\frac{-Z_F}{Z_1}=\frac{-R}{1/j\omega C}=-j\omega CR$

$\left|\frac{V_0}{V_S}\right|=\omega CR$