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Resistance of P-N Junction

For the circu...

Question

For the circuit shown below, the value of $V_{0}$ is ___ sin $ω t$ mV. (Assume thermal voltage $V_{T} = 26$ mV and cut in voltage $V_{γ} = 0.7 V$ , (capacitor is short circuited at signal frequency).

0.24

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Solution

The correct option is A 0.24
$V_{0} = \frac{r_{d} | | 8.6 k}{r_{d} | | 8.6 k + 1 k} \times V_{i n}$

Where, $I_{d} = \frac{V_{T}}{I_{d c}}$

$I_{d c} = \frac{5 - 0.7}{8.6 k} = 0.5 m A$

$r_{d} = \frac{26}{0.5} = 52 Ω$

$∴$ $V_{0} = \frac{52 | | 8.6 k}{52 | | 8.6 k + 1 k} \times 5 s i n (ω t) m V$

$= 0.246 s i n ω t m V$

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V_{0}

ω t

V_{T} = 26

V_{γ} = 0.7 V

V_{A} i s (A s s u m e, V_{γ} = 0.7 V)

V_{z} = 5.6 V

r_{d} = 100 Ω,

R_{0}

V_{T} = 26

V_{B E} (o n) = 0.7 V

V_{0}

Q_{1}

Q_{2}

I_{C} 1 = 10 I_{C 2}

V_{T} = 26

V_{1} = 25

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