For the circuit shown in figure the Boolean expression for the output Y in terms of inputs P, Q, R and S is
A
¯¯¯¯P+¯¯¯¯Q+¯¯¯¯R+¯¯¯¯S
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B
(P+Q)(R+S)
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C
(¯¯¯¯P+¯¯¯¯Q)+(¯¯¯¯R+¯¯¯¯S)
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D
P+Q+R+S
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Solution
The correct option is DP+Q+R+S Y=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(¯¯¯¯P.¯¯¯¯Q).(¯¯¯¯R.¯¯¯¯S)∵¯¯¯¯¯¯¯¯¯¯¯¯¯¯(¯¯¯¯A.¯¯¯¯B)=(A+B) ∴Y=¯¯¯¯¯¯¯¯¯¯¯¯¯¯P.¯¯¯¯Q+¯¯¯¯¯¯¯¯¯¯¯¯¯R.¯¯¯¯S ⇒Y=(P+Q+R+S)