Question

For the circuit shown in figure, the impedance of the circuit will be

• A. $50\Omega$
• B. $60\Omega$
• C. $90\Omega$
• D. $120\Omega$

Answer 1

Answer: (B)

$60\Omega$

Current through inductance, $i_L=\frac{90}{30}=3A$
Current through capacitor, $i_C=\frac{90}{20}=4.5A$
Net current through circuit
$i=i_C-i_L=1.5A$
$\therefore$ Impedence of the circuit
$Z=\frac{V}{i}=\frac{90}{1.5}=60\Omega$