Question

For the circuit shown in figure, the node voltage $V_2$ is,

• A. $-3.33V$
• B. $-1.33V$
• C. $-5.33V$
• D. $-4.33V$

Answer 1

The correct option is C $-5.33V$


Using supernode method.
$-2+\frac{V_1}{2}+\frac{V_2}{4}+7=0$
$2V_1+V_2=-20$
$V_1-V_2=-2$
$V_1=-7.33V$
$V_2=-5.33V$