For the circuit shown in the fig., the current through the inductor is 0.9 A while the current through the condenser is 0.4 A.,Then
A
Current drawn from generator I=1.13A
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B
ω=1/(1.5LC)
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C
I=0.5A
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D
I=0.6A
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Solution
The correct option is CI=0.5A The current drawn by inductor and capacitor will be in opposite phase. Hence net current drawn from generator =IL−IC=0.9−0.4=0.5amp