Question

For the circuit shown in the figure, determine the current$l$ in the circuit and the potential difference across the terminals of the battery?

Answer 1

Given:

For the circuit shown in the figure:

Formula used:

$I=\frac{R}{V}$

Where,

$I$ is the current

$R$ is the Resistor.

$V$is the voltage

Apply the formula for the given values:

$I=\frac{4}{5}\text{=0.8A and}V=E=4\text{volt.}$

The potential difference across the terminals of the battery is$\text{0.8A}$ and $4volt$.