For the circuit shown in the Figure, the current through the inductor is 0.9 A while the current through the condenser is 0.4 A
A
current drawn from generator I = 1.13 A
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B
ω=1(1.5LC)
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C
I = 0.5 A
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D
I = 0.6 A
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Solution
The correct option is C I = 0.5 A The current in inductor and capacitor is always at an phase difference of 180o for V=Vosinωt Capacitor, i=iosin(ωt−π2) Inductor, i=iosin(ωt+π2) So, the current from both branches will be 0.9+(−0.4)=0.5A