Question

For the circuit shown in the figure, the total energy stored in the capacitors is

• A. $120\mu J$
• B. $30\mu J$
• C. $60\mu J$
• D. $20\mu J$

Answer 1

The correct option is C $60\mu J$


As you can observe, this is series arragement the circuit can be redrawn like this

$C_{eq}=\frac{C_1{C}_2}{C_1+C_2}=\frac{6}{5}\mu F$
Energy stored in the capacitors is given by
$U=\frac{1}{2}{C}_{eq}{V}^2=\frac{1}{2}\times \frac{6}{5}\times 100=60J$