Question

For the circuit shown in the following diagram, What is the value of

1. current through 6$\Omega$ resistor?

2. potential difference across 12$\Omega$ ? [3 MARKS]

Answer 1

Each point: 1.5 Mark

1. For current through 6 $\Omega$

Current from 4 V battery flows through first parallel branch having 6$\Omega$ and 3$\Omega$ in series.

Current in this branch

I = $\frac{4}{9}$ = 0.44 A

2. For p.d. across 12$\Omega$

Current through second parallel branch

I = $\frac{4}{15}$ A

P.D. across 12$\Omega$ , V = $\frac{4}{15}\times 12=3.2V$