Question

For the circuit shown in the following diagram what is the value of

(i) Current through 6 $\Omega$ resistor

(ii) Potential difference across 12$\Omega$

• A. 0.44A& 1.6 V
• B. 0.44 A & 3.2 V
• C. 0.18A & 3.2 V
• D. 0.18 A & 1.6 V

Answer 1

The correct option is B

0.44 A & 3.2 V

(i) For current through $6\Omega$
Current from 4V battery flows through first parallel branch having $6\Omega$ and $3\Omega$ in series.
$I=\frac{4}{9}=0.44A$
(ii) For potential differnece across $12\Omega$
Current through second parallel branch
$I=\frac{4}{15}A$
P.D. across $12\Omega$
$V=\frac{4}{15}\times 12=3.2V$.