Question

For the circular shaft AB, as shown in the figure below, a torque 'T' is applied at section XX at C, such that b/a = 1.5. The shaft is uniform in section.


What is the ratio of $\frac{T_A}{T_B}$?

• A. 2
• B. 1.5
• C. 0.67
• D. 0.5

Answer 1

The correct option is B 1.5

$T_A\times a=T_B\times b$

$\therefore \frac{T_A}{T_B}=\frac{b}{a}=1.5$