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For the coagu...

Question

For the coagulation of $100 m L$ of arsenious sulphide solution, $5 m L$ of $1 M$ $N a C l$ is required. What is the coagulating power of $N a C l$ ?

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Solution

Total volume after addition of $5 m L$ of $1 M$ $N a C l$ solution $= 105 m L$
Thus, $105 \times$ molarity of $N a C l$ in colloidal solution = $5 \times 1$
Molarity of $N a C l$ in colloidal solution $= \frac{5}{105}$
Concentration in millimole $= \frac{5}{105} \times 100$ $= 47.6$

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